Question

consider line "a" that passes through (14,2) and (28,6) write an equation for line "a".

Answer 1

Step 1:
FInd the slope.

Step 2:
use, \[y-y_1 = m(x-x_1) \]To find the equation.

Answer 2

\[y-y _{0}=m(x-x _{0})\]
m= 6-2/28-14
just substitute\[ y _{0} ,x_{0}\]

Answer 3

y-2=2/7(x-14)
rearanging you can put it in y=mx +b form

Answer 4

(y-y1)/(x-x1)=(y2-y1)/(x2-x1)
(y-2)/(x-14)=(6-2)/(28-14)
(y-2)/(x-14)=4/14
y-2=2(x-14)/7

Solving the above will give you the equation of line a .

Answer 5

(y2-y1)/(x2-x1) -> this is the slope m of the line