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realize the denominator of
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\[\sqrt{18\div}\sqrt{3}\]
sqrt18 * sqrt3 sqrt 54 sqrt(9*6) 3sqrt6 ------------- = --------- = -------- = --------- =sqrt6 3 3 3 3
and also \[3\div6- \sqrt{5}\]
- for text of this exersice is right : ratzionalize the denominator
ok ?
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3 --- 6-sqr5
i need help with that one as well ^^^
- when in denominator is 6-sqrt5 how you will can ratzionalize it ? - how you will get from 6-sqrt5 one square perfect ? - you can multiply it by ... ?
3?
no - you need to us formula a^2 -b^2 =(a-b)(a+b)
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- so if (a-b)=6-sqrt5 than what will be (a+b)
would i multiply like this:|dw:1334689380100:dw|
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