Question

A ball is dropped from the top of a 286foot
building.How many seconds will it take to hit the
ground if the height is given by h = −16t2 + s,where (s) is the initial height?

Answer 1

when the ball hits the ground the height is zero:
0 = -16t^2 + 286

16t^2 = 286
t^2 = 286/16
\[t = \sqrt{286/16}\]
t =about 4.2s

Answer 2

thank you :)

Answer 3

no problem