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Simplify log6 4x + log6 5x + log6 2x
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log 6 4x + log 6 5x + log 6 2x= log 6 (4x*5x*2x)
\[\log _{6}(4x \times5x \times2x) = \log _{6}(40x^3)\]
thankss
Love these....\[\log_6 (4x) + \log_6 (5x) + \log_6 (2x)=\log_6(40x^3)\]
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