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Mathematics 9 Online
OpenStudy (anonymous):

tanx=(1-cos2x)/sin2x

OpenStudy (anonymous):

is it (1-cos2x)/sin2x or 1-(cos2x/sin2x) ?

OpenStudy (anonymous):

the first one

OpenStudy (anonymous):

ok thanks

OpenStudy (alexwee123):

is that cos^2(x) or just cos2x? and is it same with the sine?

OpenStudy (anonymous):

just cos 2x

OpenStudy (anonymous):

and same with sine 2x

OpenStudy (alexwee123):

wait

OpenStudy (alexwee123):

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