Question

solve x2+6x=-7 by completing the square!

Answer 1

ax^2 +bx + c to complete the square is (b/2) and add to both sides

(6/2)^2 = 9

x^2 + 6x + 9 = -7 + 9

(x +3)^2 = 2

now take the square root of both sides

\[x + 3 = \pm\sqrt{2}\]

subtract 3 from both sides

\[x = -3 \pm \sqrt{2}\]

Answer 2

thanks!