Question

graph the function by hand. give the coordinates of the vertex.
f(x)= -3(x-3)^2

Answer 1

the parabola is concave down with a vertex at (3, 0)

Answer 2

how did you find that answer?

Answer 3

and y intercept is y = -27

Answer 4

there are lots of ways in the factorised form given

y = (x -h)^2 + k the vertex is (h, k)

in your question h = 3 and k = 0

in the parabola y = ax^2 + bx + x

a determines concavity a : positive concave up a negative concave down

in your question a = -3 which comes from y = -3(x^2 -6x + 9)

so concave down

Answer 5

y -intercept.... let x = 0