A person 6 ft tall stands 10 ft from point P directly beneath a lantern hanging 30 ft above the ground, as shown in the figure below. The lantern starts to fall, causing the person’s shadow to lengthen. Given that the lantern falls 16t2 ft in t seconds, how fast will the shadow be lengthening when t = 1?

Question

anonymous · Answer

i got lost after getting the proportions which is L/(L +1O) = 6 / (3O -s )

anonymous · Answer

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