Question

PLEASE HELP

What is the 41st term of the arithmetic sequence where a1 = 15 and a15 = –41 ?

Answer 1

\[\large a_n= a_1+ (n-1)d\]\[\large a_1=15\]\[\large a_{15}=a_1+14d\]

Answer 2

\[\large a_{15}=-41\]\[\large a_1=15\]
Substitute and find d

Answer 3

\[\large \text{After finding d ,We know that}\]\[\large a_{41}=a+(41-1)d=a+40d\]
Substitute a1and d & find a41

Answer 4

wait so do i solve it like that or? im sorry Im confused