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factor 16x8-y4
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difference of -3 product of -28 the numbers must be .....four and minus seven
and by difference i mean summ
yeah thanks
where did it go?
\[ x^2-3xy-28y^2 = x^2 + (4xy-7xy)-28y^2 = x(x+4y)-7y(x+4y)=?\] Sorry I made some mistakes on the signs just now :(
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k thanks
so \[x^2-3xy-28y^2=(x+4y)(x-7y)=x^2+4xy-7xy-28y^2\]
can you solve it?
nvm
solve it lol
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What you need to do it to take out the common factor and group the rest of the terms... Can you try?
The common factor there is (x+4y) ....
is the final answer (x+4y)(x-7y)
yeahs
factor 16x8-y4 please
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i need the answer by 10:30
\[16x^8-y^4\] is a difference of squares \[(4x^4)^2-(y^2)^2\]
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