Question

log x + 5^36 = 2



x = 1
x = 11
x = 13
x = 23

Answer 1

I think that there is either something missing or I'm misinterpreting something.
I'm assuming that the log in use here is base 10. In this case:
\[\log x=2-5^{36}\]Then\[10^{2-5^{36}} = x = 10^{2}/10^{5^{36}}\]It is fairly easy to see that x is arbitrarily close to zero, leading me to believe that something is awry here.