Question

the area of an isosceles right triangle is 128 units^2 what is the perimeter of right trangle

Answer 1

is there anything more given?

Answer 2

no thats it what do you need

Answer 3

hello

Answer 4

Area here is equal to (1/2)*base*height =(1/2)*x*x=(x^2)/2
But area is equal to 128 units^2.
(x^2)/2=128
x=16

From the triangle
h^2=x^2+x^2
h=sqrt(2*x^2)
h=xsqrt2
Perimeter=x+x+h =16+16+16sqrt2=32+16sqrt2