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OpenStudy (anonymous):
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OpenStudy (kinggeorge):
Start with \(8-6x \geq 3-x\). Now, what do you think the next step should be?
OpenStudy (kinggeorge):
Close. First, add 6x to both sides.\[8-6x +6x\geq3-x+6x\]So we get \[8\geq3+5x\]Next, we subtract 3\[8-3\geq3+5x-3\]To get \[5\geq5x\]Finally, we divide by 5 to get that \[x\leq 1\]
OpenStudy (kinggeorge):
You're welcome.
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