Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

n/a

OpenStudy (anonymous):

Given the word leak, calculate the number of permutations: i done like this 1x2x3x4 = 24 and for Calculate the number of 2-letter unordered combinations: i done 24/2 = 12. now i am stock to this question "By writing out all the permutations and all the 2-letter unordered combinations, show that the two methods described above give the same result, and that the number of results are consistent with the numbers you calculated above:"???? NEED HELP!

OpenStudy (anonymous):

Unordered combinations of 4 letters taken 2 by 2 i think would be 4!/2!2! = 6 not 12

OpenStudy (anonymous):

oh ok thanks for that. what about for the first one calculate the word leak of permutations? is it correct

OpenStudy (anonymous):

yes it is

OpenStudy (anonymous):

Thanks for checking. i still dont get what he asked me to do in this question "By writing out all the permutations and all the 2-letter unordered combinations, show that the two methods described above give the same result, and that the number of results are consistent with the numbers you calculated above"

OpenStudy (anonymous):

They are asking you to right by hand all the possible permutation of the letters that you can find and then just check that the result is the same that you got using the formula...:) Same for combinations.

OpenStudy (anonymous):

oh ok. but how should i start writing by hand example please.

OpenStudy (anonymous):

could it be like leak, le,el, ka, ka, ect?

OpenStudy (anonymous):

leak: 1º leka 2º lkea 3ºklea ..........................

OpenStudy (anonymous):

and so on and on

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

thats for permutation right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

what about for the unordered compinantion

OpenStudy (anonymous):

combinations: 1º le 2º lk 3º la 4º ea 5º ek 6º ak

OpenStudy (anonymous):

do you know that you have just saved my life. i been in this question for 4 hours and didnt get it, been searching on google and still didnt get it any help! you are great and thanks for the help

OpenStudy (anonymous):

you welcome

OpenStudy (anonymous):

i am fan of your now :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!