Question

In parallelogram DEFG, Dh=x+3, HF= 3y, GH=3x-3, and HE=5y+4. Find the values of x and y?

Answer 1

HF= HE by symmetry
so
3y = 5y+4
You can solve for y


Same way for x:
DH= GH by symmetry

Answer 2

You can set two equations since diagonal of //gram bisects each other
Dh= HF =>x+3= 3y -(1)
GH= HE => 3x-3=5y+4. -(2)
(1)x3-(2)
3(x+3) - (3x-3)= 3(3y)-(5y+4)
12 = 4y-4
y=4
Can you solve x?