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x^2 − y^2 = 16 Find a polar form of the equation.
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y=+/- sqrt(x^2 -16)
I don't think that's right, I got the solution anyways.
so what ?
Or maybe it's just in a different form
write it plaese !
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r^2 cos(2theta)=16
So what? So, you gave me a wrong answer. But not like it matters. I solved it anyways. thanks for trying.
ok bye
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