In the parallelogram AXYZ, line segment AT = 4y – 2, line segment TY = 6x -12, line segment TX = 14, line segment ZT = 2x + 12. Find the value of x and y.

A. x = 4, y = 6
B. x = 48, y = 28
C. x = 6, y = 28
D. x = 6, y = 4

Question

In the parallelogram AXYZ, line segment AT = 4y – 2, line segment TY = 6x -12, line segment TX = 14, line segment ZT = 2x + 12. Find the value of x and y.

	A.	x = 4, y = 6
	B.	x = 48, y = 28
	C.	x = 6, y = 28
	D.	x = 6, y = 4

anonymous · Answer

attachment

anonymous · Answer

i'm sure you mean parallelogram AYXZ right?

anonymous · Answer

Yes.

anonymous · Answer

nevertheless,  the diagnols of any parallelogram bisect each other which means AT = TX.  now you can solve the equation 4y-2 = 14...

anonymous · Answer

solve for y...  y=  ???
do you need help?

anonymous · Answer

Yes I need help(:

apoorvk · Answer

Diagonals of a parallelogram bisect each other.
So, AT=TX                and             ZT=TY

or, 4y-2 = 14           and        6x-12 = 2x +12



Solve those two, get x&y and enjoy!

anonymous · Answer

So do I just plug in a number then to find x? I don't get it.

apoorvk · Answer

can you solve a linear equation in one variable like for example, a+3 = 6, so how much is 'a'?

anonymous · Answer

3.

apoorvk · Answer

same way we solve
4y-2 = 14
adding 2 to both sides,
4y =  16
dividing both sides by 4
y=4

get it?

anonymous · Answer

I think so. So I do that for the two problems then?

apoorvk · Answer

yeah solve the same way for the second equation there.

anonymous · Answer

I got confused again on this. I need to be refreshed on it.