Question

sinv=1/5. i need to find sin(2v)

Answer 1

sin(v) = 1/5

sin^2(v) = (1/5)^2

sin^2(v) = 1/25

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sin^2(v) + cos^2(v) = 1

1/25 + cos^2(v) = 1

cos^2(v) = 1-1/25

cos^2(v) = 24/25

cos(v) = sqrt(24/25)

cos(v) = sqrt(24)/sqrt(25)

cos(v) = 2*sqrt(6)/5


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sin(2v) = 2*sin(v)*cos(v)

sin(2v) = 2*(1/5)*(2*sqrt(6)/5)

sin(2v) = 4*sqrt(6)/25

Answer 2

thanks guys

Answer 3

heres a triangle if u need a picture