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Find a vector perpendicular to the plane defined by the equation x-5y+10z=20
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umm, the normal IS perp to the plane
Hah, was just checking that I had that right. The coefficients on the equation of a plane is the normal vector.
Oh yeah, duh. Thanks that was a stupid question
lol, it was a question designed to see how well you are aware of what your learning ;)
haha yeah I didn't write that down in my notes, I just did a triple cross example thing, which proves the same thing. But still thanks
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