Question

A 390 g mass vibrates according to the equation x = 0.38 sin (5.48t) where x is in meters and t is in seconds. Determine the frequency.

Answer 1

The period of x = A*sin(Bt) is T = 2pi/B


In your case, B = 5.48. So the period is T = 2pi/5.48 = 1.14656


The frequency, f, is equal to one over the period. So

f = 1/T = 1/1.14656 = 0.87217


So the frequency is 0.87217

Answer 2

thank you!