Question

determine the equation of the line that is tangent to y=2tanx, where x=pi/4

Answer 1

\[y-y(x0)=m*(x-x0)\] where \[m=y'(x0)\]
\[y'=(\sec(x))^{2} \]
\[x0=pi/4\]

Answer 2

sub pi/4 in the orignal equation to get y value?

Answer 3

woah, can u show the steps to how u solved for x when sec^2x=0, and

Answer 4

it's not zero sec²(pi/4)=2