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OpenStudy (anonymous):
simplify the expression: 1/cotx-secx/cscx
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OpenStudy (anonymous):
1/(cosx/sinx) - (1/cosx)/(1/sinx) = (sinx/cosx) - (sinx/cosx) = 0
OpenStudy (anonymous):
@jaersyn how u get (sinx/cosx)-(sinx/cosx)?
OpenStudy (anonymous):
cotx = cosx/sinx secx = 1/cosx cscx = 1/sinx
OpenStudy (anonymous):
also tanx = sinx/cosx
OpenStudy (anonymous):
@jaersyn |dw:1334812473900:dw| so it look like this? then what did u do from there to get (sinx/cosx)-(sinx/cosx)?
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