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Mathematics 20 Online
OpenStudy (anonymous):

simplify the expression: 1/cotx-secx/cscx

OpenStudy (anonymous):

1/(cosx/sinx) - (1/cosx)/(1/sinx) = (sinx/cosx) - (sinx/cosx) = 0

OpenStudy (anonymous):

@jaersyn how u get (sinx/cosx)-(sinx/cosx)?

OpenStudy (anonymous):

cotx = cosx/sinx secx = 1/cosx cscx = 1/sinx

OpenStudy (anonymous):

also tanx = sinx/cosx

OpenStudy (anonymous):

@jaersyn |dw:1334812473900:dw| so it look like this? then what did u do from there to get (sinx/cosx)-(sinx/cosx)?

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