43=7w-15-5w i know im asking questions a lot but i have to because i am too far behined and dont get it
So it looks like the first step you should take is to combine like terms. Such as the 7w and the -5w. Do you understand how to do that?
yes
Ok, so what do you get after you combine those terms? What does the equation look like?
well i know im supposed to find out what W is...but it would be 2w right
Yup. Which means your equation would look like \(43=2w-15\) right? Does that make sense so far?
yes thanks
Ok, so do you know what to do next?
multiply 43 by both sides?
That would yield \(43*43=43*(2w-15)\)... that seems to be more complicated. Not less complicated. Let's try something else. What's your next idea?
Multiply 15 by both sides? Im really stupid hahaha so yeah
You are correct that we want to do something with the 15, but multiply isn't quite it. We want to get rid of the \(-15\) on the right hand side. Make it completely disappear (or equal zero - either way you want to think about it).
okay got it
Alright, so what are you going to do?
so what we do to one side we do to the other
Well, yes, but what can we do to both sides to make the 15 disappear?
divide
Nope. It's a \(-15\), so we should add 15 to both sides.
oh okay
\(43=2w−15\) \(+15\) \(+15\)
What does that make?
if its on one side then 58=2w right
You got it, boss. So now you're left with \(58=2w\). Any idea about how to find \(w\)?
im guessing multipication...
Sorry, but no. Division, actually. When you're working with these, generally addition and subtraction are used for moving things from one side of the equation to the other and multiplication is used to *attach* numbers to variables/letters and division is used to *separate* numbers from variables/letters. Make sense?
Yes:)
Ok, so how would you finish out this problem?
would W be 29?
It is indeed! :) Excellent job!
Thank you so much:)
Not a problem, happy to help! Please do note that it is nice to award a medal to me if you thought I had the best answer. It's a way to say "Thanks" to the user who helps you out the most.
Thanks:)
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