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OpenStudy (anonymous):
cosx dy = y (sinx-y)dx
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OpenStudy (anonymous):
Are you trying to verify, solve?
OpenStudy (anonymous):
x= y+1/x, D=0
OpenStudy (experimentx):
I guess it could be cosx dy = y (sinx-y)dx => dy/dx = y(sinx - y)/cosx => dy/dx = ytanx - y^2secx => dy/dx - ytanx = -y^2 secx http://en.wikipedia.org/wiki/Bernoulli_differential_equation
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