Question

The current I at time t seconds in a series circuit containing only a resistor
with resistance 10 ohm, an inductor with inductance 0.5 henry, and a
steady 12 volt battery connected at time t = 0 is given by the formula
I = (6/5) (1 − e^(−20t)) explain what happens to the current for t ≥ 0.

Answer 1

re wrote the question

Answer 2

as t increases to infinity, the exponential approaches 0 bcos its the sign for -20t is negative..so whats left is 6/5