Question

plz help me.........
(x^2-2xy-y^2)dx=(x+y)^2dy

Answer 1

can any one get the ans?????????

Answer 2

yup i m trying to slove

Answer 3

\[y=vx\]Use this substitution.

Answer 4

\[\frac{dy}{dx} = v + x\frac{dv}{dx}\]

Answer 5

kk let me try ya i got u.........

Answer 6

is this a question to prove?

Answer 7

\[(x^2-2xy-y^2)dx=(x+y)^2dy \\
\frac {dy}{dx}=\frac {x^2-2xy-y^2} {(x+y)^2}=\frac{(x-y)^2}{(x+y)^2}
\]

Answer 8

bt (x-y)^2 == x^2-2xy +y^2 na?????

Answer 9

nope this que for solve

Answer 10

what are we trying to find?