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Find the altitude of an equilateral triangle if one of its sides measures 12 cm.
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Height: \(\frac{\sqrt{3}}2 \times \)side
\[6 \sqrt{3} \]
144=36 +h^2 h=sqrt(144-36) h=sqrt108 = or sin60=h/12 sqrt3 h ----- = ----- ---- h= 6sqrt3 2 12
my pleasure yw good luck bye
|dw:1334840916061:dw| Draw this diagram may help you find out the answer! Good luck :) PS: you can use sine ratio since it is a right angle triangle!~
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