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fractions roots,radical root functions help
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\[\sqrt{\left(\begin{matrix}8 \\ 9\end{matrix}\right)} +\sqrt{\left(\begin{matrix}18 \\ 36\end{matrix}\right)}\]
\[(7\sqrt{2})/6\]
\[\frac{\sqrt{8}}{\sqrt{9}}=\frac{2\sqrt{2}}{3}\] and similarly \[\frac{\sqrt{18}}{\sqrt{36}}=\frac{3\sqrt{2}}{6}\]
add to get gepard's answer
that's right
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