Question

(16x^3+4x^2-144)÷(4x-8)

Answer 1

\[\frac{16x^3+4x^2-144}{4x-8}=\frac{4(4x^3+x^2-36)}{4(x-2)}=\frac{4x^3+x^2-36}{x-2}\]

Answer 2

thank you!

Answer 3

Are you supposed to finish the division using long division or synthetic division or were you only supposed to reduce the fraction to lowest terms?

Answer 4

i was suppose to use long division