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The function f is twice differentiable with f(2)=1, f'(2)=4, and f''(2)=3. What is the value of the approximation of f(1.9) using the line tangent to the graph of f at x=2?
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\[f(x+\Delta x)\approx f(x)+f'(x)(\Delta x)\] \[f(1.9)\approx f(2)+f'(2)(1.9-2)\] \[f(1.9)\approx 1+4(0.1)=1.4\]
Whoops. That should be 1-4(0.1)=0.6. :D
what is the triangle symbol? i havent learned that yet :(
That triangle symbol is called delta. It means some sort of change in a quantity.
thanks!
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No problem. :D
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