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stuck help!:) find the sum of 2sqrt6 and sqrt24
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Hint: try finding perfect square factors in 24 and removing them by the rule \( \sqrt{ab} = \sqrt{a}\sqrt{b} \)
what he said, multiply the square roots then square root the product and multiply by the coefficient
my way to do this is to factor 24 into prime numbers so... \(\large \sqrt{24} = \sqrt{(2)(2)(2)(3)}\) take out of the sqrt all numbers that appeared twice
yep did it and got 4 sqrt 6
multiply whats is under the square root
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\(\Huge \checkmark\) @katlin95
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