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Mathematics 14 Online
OpenStudy (anonymous):

How do I do this?!Factor completely: 2x3 + 10x2 + 4x + 20

OpenStudy (anonymous):

Group first: \[(2x ^{3}+10x ^{2}) + (4x + 20)\] Factor out common factor of term in each group: \[2x ^{2}(x+5) + 4(x+5)\] Link the proper terms: \[(2x ^{2}+4)(x+5)\]

OpenStudy (anonymous):

thank you so much!

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