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Fill in the blank with the expresion Intergral (x^3-4x)dx=? +C
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Increase the power of each term and then divide that term by that power.
As in increase the power by 1...
so what would it be
Intergral (x^3-4x)dx=x^4/4-2x^2 +C
thats not correct, homeowrk isnt accepting that answer
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How come? Let's wait and see if someone has a different answer. :D
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