Question

can someone please check my work?

Answer 1

wrong unfortunately

Answer 2

remember the log rules \[3logx = logx ^{3}\]
and \[logx ^{3} -\log y = \log(x ^{3}/y)\]

Answer 3

with logs there are a few rules:
any + or - is really a * and /sign.
2) the number before the LOG is the exponent .

Answer 4

and then \[\log(x ^{3}/y) + logz = \log(x ^{3}z/y)\]