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add 8+ x-1 divided by x+4?
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\[\LARGE 8+ \frac{x-1}{x+4}\] ? or... \[\LARGE \frac{8+x-1}{x+4}\]
first one
\[\LARGE 8+{x-1 \over x+4}={8(x+4)\over x+4}+{x-1\over x+4}=\] can you do it now? :)
no it still confuses me
ok... Don't worry, we'll do it together ;) \[\LARGE {8(x+4)\over x+4}+{x-1\over x+4}={8\cdot x+8\cdot 4 \over x+4}+{x-1\over x+4}=\] \[\LARGE {(8x+32)+(x-1)\over x+4}\] can you do it now ? :)
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