Question

how do you solve 9^6a <31

Answer 1

\[\LARGE 9^{6a}<31\]
\[\LARGE \log(9)^{6a}<\log(31)\]
\[\LARGE 6a\cdot \log(9)<\log(31)\]
\[\LARGE 6a<\frac{\log(31)}{\log(9)}\]
\[\LARGE 6a<\log_9(31 )\]
\[\LARGE a<\frac{\log_9(31)}{6}\]
UGLY ANSWER ! :( isn't it?