Question

Identify the 42nd term of an arithmetic sequence where a1 = –12 and a27 = 66.

Answer 1

i got like 2.somthing

Answer 2

I'm doing something wrong

Answer 3

common difference =(66 - (-12)) / (27 - 1) = 78/26 = 3
a(42) = -12 + 3(42 - 1) = 111

Answer 4

how did you get that

Answer 5

a(n) = a(1) + (n - 1)d
66 = -12 + d(27 - 1)
78 = 26d
d = 3