Question

how do you solve log(10) 19

Answer 1

Help @angela210793

Answer 2

lets goo (:

Answer 3

then our hero comes pls @Hero

Answer 4

Hint:

\[\log_{10}(19) = y \]

Answer 5

are we tryin to find out y ??but hoow?

Answer 6

i really need help with this

Answer 7

what are trying to find out??

Answer 8

Here's the formula:

\[\log_x(a) = y \space \text{is equivalent to} \space x^y = a\]

Answer 9

In other words,

\[\log_{10} (19) = y \space \text {is equivalent to} \space 10^y = 19\]

Answer 10

So basically we can just deal with

\[10^y = 19\]

Now use properties of logs to take y out of the exponent. You do that by taking logs of both sides:

\[y \log(10) = \log(19)\]
Then you isolate y:
\[y = \frac{\log(19)}{\log(10)}\]

Answer 11

You end up with y = 1.27875

Answer 12

approximately