Question

3^x =2 , 2^y=5 , 5^z= 3 show that xyz=1

Answer 1

3^x=2
xln3=ln2
x=(ln2)/(ln3)

similarly,
y=(ln5)/(ln2)
z=(ln3)/(ln5)

xyz=(ln2)/(ln3) (ln5)/(ln2) (ln3)/(ln5)
=1