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Solve for pi : C=2^pi r
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\[c=2^\pi r,2^\pi=\frac{c}{r},\pi=\frac{\ln c-\ln r}{\ln 2}\]
?
2^π=c/r he just natural logged both sides then the pi comes down π* ln(2)= ln(c/r)
So it's c over r?
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