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What is the 7th term of the geometric sequence 3, 9, 27
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\[3^{n}\] n=7 so..
well.. if a_1=3 ... \[\LARGE q=\frac{9}{3}=3 \] \[\LARGE a_n=a_1\cdot q^{n-1}\] \[\LARGE a_7=3\cdot 3^{7-1}\] ...
can you do it now ?
yup i got it
if u want to solved more geometri problem just do like @kreshnik said..
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