Question

Solving the equation 3^3x-2 = 3^5-2x for x, you get x =

A)7/5
B)log3 7/5
c)7/3
d)log3 3/5
e)7

Answer 1

that's : \[3^{3x-2} = 3^{5-2x}\]

Answer 2

\[\LARGE 3^{3x-2}=3^{5-2x} \quad \iff 3x-2=5-2x\]
so when you have the same bases just take exponents...

3x-2=5-2x
3x+2x=5+2
5x=7
can you do it now ? :)

Answer 3

7/5 ....thanks. I actually did it the long way and i didn't want to submit just to make sure.

Answer 4

:) ... My pleasure.