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Find the exact length of the polar curve . . .
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\[r=\theta\] \[0\le \theta \le2pi\]
looks like it's going to be spiral ...|dw:1334966504484:dw|
shouldnt we add up all the tangents?
\[ length = \int_{0}^{2\pi} r d\theta\]
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Oh ... i got it wrong.
you got the dt right :)
Not really, I got the area ... I think ... LOL http://tutorial.math.lamar.edu/Classes/CalcII/PolarArcLength_files/eq0013M.gif
http://tutorial.math.lamar.edu/Classes/CalcII/PolarArcLength_files/eq0006M.gif
\[\int \sqrt{t^2+1}dt\] right?
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http://www.wolframalpha.com/input/?i=integrate+sqrt%281%2Bx%5E2%29+dx+from+0+to+2pi
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