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OpenStudy (anonymous):
Hi, could someone help me with this?
(Please reply so i can draw some triangles that go along with the problem).
Thanks.
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OpenStudy (anonymous):
yes go on
OpenStudy (anonymous):
thanks, im drawing.
OpenStudy (anonymous):
Whats the question?
OpenStudy (anonymous):
I have to draw first, but..
Triangle RST and JKL are similar. Which choice shows the equations that can be used to find the area of triangle JKL?
OpenStudy (anonymous):
A. First use 9/18=h/12 and then use area= 1/2 (12h)
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OpenStudy (anonymous):
do width times hieght and figure out the height multiply it by the width on both triangles and compare
OpenStudy (anonymous):
B. First use 9/18 = h/12 and then use area= 12h
OpenStudy (anonymous):
Wait please, I am going to draw.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
well, there's these 2 triangles.
RST has a height of 9 cm and a base of 18 cm and JKL has a height of h cmand base of 12 cm.
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OpenStudy (anonymous):
then do 9 times 18 and get ur answer add that togeter with 12 and a triangle shld be 180 degrees so then do 180 divided by 12 and u get ur answer
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