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Mathematics 11 Online
OpenStudy (anonymous):

tangent ratio, # 4

OpenStudy (anonymous):

OpenStudy (akshay_budhkar):

\[\tan 43 = {x \over 12 }\]

OpenStudy (kropot72):

Can you state the ratio that equals the tangent of 43 degrees?

OpenStudy (saifoo.khan):

\[\tan \theta = \frac{opposite}{adjacent } \]

OpenStudy (akshay_budhkar):

\[\tan \theta = {opposite side \over adjacent side }\]

OpenStudy (akshay_budhkar):

Also tan 43 = 0.93. So you just need to substitute. Hope it helps

OpenStudy (anonymous):

Pg 434 #4 a. 10.8 b. 11.2 c. 12.6

OpenStudy (akshay_budhkar):

11.2 is the closest

OpenStudy (anonymous):

what about # 10?

OpenStudy (akshay_budhkar):

i am sorry it is unclear.

OpenStudy (akshay_budhkar):

i cant see the diagram properly

OpenStudy (anonymous):

let me re post

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