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The function g(x)-->4-3sinx is defined for the domain \[{pi /2} \le x \le A\]where A = 3pi/2. For which value of A, find the value of (g^-1)(3)
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4-3sinx = 3 solve x ..
And then?
what is the value of x??
sinx= 1/3
But then there's also inverse of g, so how do I get to the final answer?
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let x = a for now, you know for +a, sin(a) = sin(2\(\pi\) - a) and \(1\pi/2\)< \(\pi - a\) < \(3\pi/2\)
not really following, but carry on...
http://www.wolframalpha.com/input/?i=pi+-+arcsin%281%2F3%29 answer in radians
Thanks :)
yw.
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