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Solve 3x2 + 2x - 4 = 0 The 3x2 is 3x squared . Plz help :)
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Use quadratic formula: (-2 +/- SQRT(4 - 4*(-4)*3))/6 (-2 +/- SQRT(4+48))/6 (-2 +/- SQRT(52))/6
\[3x^2 + 2x - 4 = 0\]\[(x+1/3)^2=13/9\]\[x=1/3(-1-\sqrt13)\]\[x=1/3(\sqrt13-1)\]
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