Question

Solving the equation C = Ba^t/D – K for t using logarithms with base a gives you t =

A) Dloga (C/B + K}
B) Dloga (C+K/B}
C) loga (C+K/B} /d
D) loga (D(C+K) /B }
E) 1/D loga (C/B} +K

Answer 1

that is: \[C = Ba ^{t/D} - K\]

Answer 2

D.

Answer 3

It was B, but thanks anyway.

Answer 4

oh sorry....i agree.!!!