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OpenStudy (anonymous):
Use the elimination method to solve the given system of equations. 5x +y=3 10x +2y=4 a.(0,3) b.(0,10) c.no solutions d.infinitely many solutions
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OpenStudy (kropot72):
If (5x + y = 3) is multiplied by 2 on both sides it becomes 10x + 2y = 6. But the second equation says 10x + 2y = 4. Therefore there can be no solutions.
OpenStudy (anonymous):
Thanks Again :)
jhonyy9 (jhonyy9):
multiply first by -2 and assum those 5x+y=3 *(-2) -10x -2y =-6 10x +2y =4 -------------- 0 0 =-2 - so than result that the system have not solutions
OpenStudy (kropot72):
You're welcome:)
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