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Maria inscribed a quadrilateral ABCD in a circle, as shown below. If the measure of arc BCD is 260°, what is the measure of angle BCD? 80˚ 40° 65° 50°
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angle BAD should be 130 not 135
another way to think of it is that arc BAD is 360 - 260 = 100 degrees So by the inscribed angle theorem, angle BCD = 1/2(arc BAD) = 1/2(100) = 50
if the measure of arc BCD is 260 then the measure of arc BAD would be 100 (260+100=360) and then the the measure of angle BCD would be the half of arcBAD=50
Thank you both!<3
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you're welcome
oh yeaa (:
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